Base | Representation |
---|---|
bin | 100110111110000110000… |
… | …0010010000000111011001 |
3 | 200222000211200002200221101 |
4 | 1031330030002100013121 |
5 | 1200223120142310001 |
6 | 15220305140111401 |
7 | 1061650214656123 |
oct | 115741402200731 |
9 | 20860750080841 |
10 | 5356026135001 |
11 | 1785529138273 |
12 | 72604a395561 |
13 | 2cb0c027c339 |
14 | 1473396ac213 |
15 | 944c8821a01 |
hex | 4df0c0901d9 |
5356026135001 has 2 divisors, whose sum is σ = 5356026135002. Its totient is φ = 5356026135000.
The previous prime is 5356026134989. The next prime is 5356026135059. The reversal of 5356026135001 is 1005316206535.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5347882877401 + 8143257600 = 2312549^2 + 90240^2 .
It is a cyclic number.
It is not a de Polignac number, because 5356026135001 - 25 = 5356026134969 is a prime.
It is not a weakly prime, because it can be changed into another prime (5356026135301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2678013067500 + 2678013067501.
It is an arithmetic number, because the mean of its divisors is an integer number (2678013067501).
Almost surely, 25356026135001 is an apocalyptic number.
It is an amenable number.
5356026135001 is a deficient number, since it is larger than the sum of its proper divisors (1).
5356026135001 is an equidigital number, since it uses as much as digits as its factorization.
5356026135001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 37.
The spelling of 5356026135001 in words is "five trillion, three hundred fifty-six billion, twenty-six million, one hundred thirty-five thousand, one".
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