Base | Representation |
---|---|
bin | 11000010110111111111001… |
… | …01000100101001111001011 |
3 | 21000122221012200210111100101 |
4 | 30023133330220211033023 |
5 | 24010114224031121011 |
6 | 305532123105550231 |
7 | 14166033431236660 |
oct | 1413377450451713 |
9 | 230587180714311 |
10 | 53566775645131 |
11 | 160825a6406841 |
12 | 6011724945377 |
13 | 23b742c8000a8 |
14 | d32908011a67 |
15 | 62d5dc4d82c1 |
hex | 30b7fca253cb |
53566775645131 has 8 divisors (see below), whose sum is σ = 61219313771264. Its totient is φ = 45914272920360.
The previous prime is 53566775645129. The next prime is 53566775645161. The reversal of 53566775645131 is 13154657766535.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53566775645131 - 21 = 53566775645129 is a prime.
It is a super-2 number, since 2×535667756451312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53566775645161) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5524605 + ... + 11732638.
It is an arithmetic number, because the mean of its divisors is an integer number (7652414221408).
Almost surely, 253566775645131 is an apocalyptic number.
53566775645131 is a deficient number, since it is larger than the sum of its proper divisors (7652538126133).
53566775645131 is a wasteful number, since it uses less digits than its factorization.
53566775645131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17700681.
The product of its digits is 238140000, while the sum is 64.
The spelling of 53566775645131 in words is "fifty-three trillion, five hundred sixty-six billion, seven hundred seventy-five million, six hundred forty-five thousand, one hundred thirty-one".
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