Base | Representation |
---|---|
bin | 110001111010101001… |
… | …011001001110101011 |
3 | 12010100021201212220212 |
4 | 301322221121032223 |
5 | 1334231400413042 |
6 | 40342223411335 |
7 | 3605122233026 |
oct | 617251311653 |
9 | 163307655825 |
10 | 53597279147 |
11 | 208042a3125 |
12 | a479753b4b |
13 | 5092109579 |
14 | 28463b21bd |
15 | 15da5ba482 |
hex | c7aa593ab |
53597279147 has 4 divisors (see below), whose sum is σ = 53625896760. Its totient is φ = 53568661536.
The previous prime is 53597279143. The next prime is 53597279171. The reversal of 53597279147 is 74197279535.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53597279147 - 22 = 53597279143 is a prime.
It is a super-2 number, since 2×535972791472 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53597279143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14305997 + ... + 14309742.
It is an arithmetic number, because the mean of its divisors is an integer number (13406474190).
Almost surely, 253597279147 is an apocalyptic number.
53597279147 is a deficient number, since it is larger than the sum of its proper divisors (28617613).
53597279147 is a wasteful number, since it uses less digits than its factorization.
53597279147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28617612.
The product of its digits is 16669800, while the sum is 59.
The spelling of 53597279147 in words is "fifty-three billion, five hundred ninety-seven million, two hundred seventy-nine thousand, one hundred forty-seven".
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