Base | Representation |
---|---|
bin | 110001111010111010… |
… | …000010111111010001 |
3 | 12010100120221200001111 |
4 | 301322322002333101 |
5 | 1334234010110442 |
6 | 40342501133321 |
7 | 3605204314012 |
oct | 617272027721 |
9 | 163316850044 |
10 | 53601644497 |
11 | 20806804955 |
12 | a47b0ba241 |
13 | 5092ca750b |
14 | 2846bcb009 |
15 | 15dab7db17 |
hex | c7ae82fd1 |
53601644497 has 2 divisors, whose sum is σ = 53601644498. Its totient is φ = 53601644496.
The previous prime is 53601644489. The next prime is 53601644533. The reversal of 53601644497 is 79444610635.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32355375376 + 21246269121 = 179876^2 + 145761^2 .
It is a cyclic number.
It is not a de Polignac number, because 53601644497 - 23 = 53601644489 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53601644497.
It is not a weakly prime, because it can be changed into another prime (53601644407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26800822248 + 26800822249.
It is an arithmetic number, because the mean of its divisors is an integer number (26800822249).
Almost surely, 253601644497 is an apocalyptic number.
It is an amenable number.
53601644497 is a deficient number, since it is larger than the sum of its proper divisors (1).
53601644497 is an equidigital number, since it uses as much as digits as its factorization.
53601644497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2177280, while the sum is 49.
The spelling of 53601644497 in words is "fifty-three billion, six hundred one million, six hundred forty-four thousand, four hundred ninety-seven".
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