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536075352150473 is a prime number
BaseRepresentation
bin111100111100011101100010…
…0111100000001000111001001
32121022002022012000011210212202
41321320323010330001013021
51030231024310122303343
65140045341134045545
7220626110652644222
oct17170730474010711
92538068160153782
10536075352150473
111458a03099191a3
125015abb29498b5
131a0178c5395bc5
149654284d7a249
1541e983ba87db8
hex1e78ec4f011c9

536075352150473 has 2 divisors, whose sum is σ = 536075352150474. Its totient is φ = 536075352150472.

The previous prime is 536075352150439. The next prime is 536075352150539. The reversal of 536075352150473 is 374051253570635.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 516017019456064 + 20058332694409 = 22716008^2 + 4478653^2 .

It is a cyclic number.

It is not a de Polignac number, because 536075352150473 - 212 = 536075352146377 is a prime.

It is a super-3 number, since 3×5360753521504733 (a number of 45 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (536075352150433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 268037676075236 + 268037676075237.

It is an arithmetic number, because the mean of its divisors is an integer number (268037676075237).

Almost surely, 2536075352150473 is an apocalyptic number.

It is an amenable number.

536075352150473 is a deficient number, since it is larger than the sum of its proper divisors (1).

536075352150473 is an equidigital number, since it uses as much as digits as its factorization.

536075352150473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 39690000, while the sum is 56.

The spelling of 536075352150473 in words is "five hundred thirty-six trillion, seventy-five billion, three hundred fifty-two million, one hundred fifty thousand, four hundred seventy-three".