Base | Representation |
---|---|
bin | 11000011000011100011001… |
… | …00101101110100000101011 |
3 | 21000211200101120111021021101 |
4 | 30030032030211232200223 |
5 | 24011422424434043133 |
6 | 310011014520022231 |
7 | 14202442152536545 |
oct | 1414161445564053 |
9 | 230750346437241 |
10 | 53616435456043 |
11 | 160a166a045789 |
12 | 601b283901977 |
13 | 23bc014c403a5 |
14 | d350994aa695 |
15 | 62ea4708137d |
hex | 30c38c96e82b |
53616435456043 has 4 divisors (see below), whose sum is σ = 54757210678560. Its totient is φ = 52475660233528.
The previous prime is 53616435456041. The next prime is 53616435456053. The reversal of 53616435456043 is 34065453461635.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 53616435456043 - 21 = 53616435456041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53616435456041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 570387611188 + ... + 570387611281.
It is an arithmetic number, because the mean of its divisors is an integer number (13689302669640).
Almost surely, 253616435456043 is an apocalyptic number.
53616435456043 is a deficient number, since it is larger than the sum of its proper divisors (1140775222517).
53616435456043 is a wasteful number, since it uses less digits than its factorization.
53616435456043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1140775222516.
The product of its (nonzero) digits is 46656000, while the sum is 55.
The spelling of 53616435456043 in words is "fifty-three trillion, six hundred sixteen billion, four hundred thirty-five million, four hundred fifty-six thousand, forty-three".
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