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53620277339 = 128173418343
BaseRepresentation
bin110001111100000001…
…001000000001011011
312010101220000022111202
4301330001020001123
51334303242333324
640344404344415
73605521560116
oct617401100133
9163356008452
1053620277339
1120816280aa2
12a4853a510b
135096acc575
14284947b57d
1515dc60e8ae
hexc7c04805b

53620277339 has 4 divisors (see below), whose sum is σ = 53620823856. Its totient is φ = 53619730824.

The previous prime is 53620277251. The next prime is 53620277357. The reversal of 53620277339 is 93377202635.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 53620277339 - 28 = 53620277083 is a prime.

It is a super-2 number, since 2×536202773392 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53620277293 and 53620277302.

It is not an unprimeable number, because it can be changed into a prime (53920277339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80999 + ... + 337344.

It is an arithmetic number, because the mean of its divisors is an integer number (13405205964).

Almost surely, 253620277339 is an apocalyptic number.

53620277339 is a deficient number, since it is larger than the sum of its proper divisors (546517).

53620277339 is a wasteful number, since it uses less digits than its factorization.

53620277339 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 546516.

The product of its (nonzero) digits is 1428840, while the sum is 47.

The spelling of 53620277339 in words is "fifty-three billion, six hundred twenty million, two hundred seventy-seven thousand, three hundred thirty-nine".

Divisors: 1 128173 418343 53620277339