Base | Representation |
---|---|
bin | 11000011000110000110110… |
… | …10110111010111010000111 |
3 | 21000212201202011002000000011 |
4 | 30030120123112322322013 |
5 | 24012112424141314033 |
6 | 310020032534531051 |
7 | 14203311322261453 |
oct | 1414303326727207 |
9 | 230781664060004 |
10 | 53627420651143 |
11 | 160a6296991419 |
12 | 602142a806a87 |
13 | 23c0075a83131 |
14 | d3581c405663 |
15 | 62ee8b698ccd |
hex | 30c61b5bae87 |
53627420651143 has 16 divisors (see below), whose sum is σ = 54364475450880. Its totient is φ = 52892595874656.
The previous prime is 53627420651111. The next prime is 53627420651171. The reversal of 53627420651143 is 34115602472635.
It is a cyclic number.
It is not a de Polignac number, because 53627420651143 - 25 = 53627420651111 is a prime.
It is a super-2 number, since 2×536274206511432 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53627420658143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 136578246 + ... + 136970332.
It is an arithmetic number, because the mean of its divisors is an integer number (3397779715680).
Almost surely, 253627420651143 is an apocalyptic number.
53627420651143 is a deficient number, since it is larger than the sum of its proper divisors (737054799737).
53627420651143 is a wasteful number, since it uses less digits than its factorization.
53627420651143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 394926.
The product of its (nonzero) digits is 3628800, while the sum is 49.
The spelling of 53627420651143 in words is "fifty-three trillion, six hundred twenty-seven billion, four hundred twenty million, six hundred fifty-one thousand, one hundred forty-three".
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