Base | Representation |
---|---|
bin | 11000011000111010000100… |
… | …11110111110011011101011 |
3 | 21000220012112012222200121101 |
4 | 30030131002132332123223 |
5 | 24012203044220311301 |
6 | 310022212132222231 |
7 | 14203545114351640 |
oct | 1414350236763353 |
9 | 230805465880541 |
10 | 53632372041451 |
11 | 160a83a7908225 |
12 | 6022390a6a977 |
13 | 23c0684822398 |
14 | d35b6bc51dc7 |
15 | 63017b1ec701 |
hex | 30c7427be6eb |
53632372041451 has 32 divisors (see below), whose sum is σ = 65051977955328. Its totient is φ = 43164952427520.
The previous prime is 53632372041343. The next prime is 53632372041463. The reversal of 53632372041451 is 15414027323635.
It is not a de Polignac number, because 53632372041451 - 243 = 44836279019243 is a prime.
It is a super-3 number, since 3×536323720414513 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (53632382041451) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 304653511 + ... + 304829503.
It is an arithmetic number, because the mean of its divisors is an integer number (2032874311104).
Almost surely, 253632372041451 is an apocalyptic number.
53632372041451 is a deficient number, since it is larger than the sum of its proper divisors (11419605913877).
53632372041451 is a wasteful number, since it uses less digits than its factorization.
53632372041451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 182011.
The product of its (nonzero) digits is 1814400, while the sum is 46.
The spelling of 53632372041451 in words is "fifty-three trillion, six hundred thirty-two billion, three hundred seventy-two million, forty-one thousand, four hundred fifty-one".
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