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53639408993 is a prime number
BaseRepresentation
bin110001111101001010…
…000110110101100001
312010110020000022012112
4301331022012311201
51334323142041433
640350330405105
73606143311412
oct617512066541
9163406008175
1053639408993
1120826058985
12a48b890795
13509aa6a681
14284bc1b809
1515de13d348
hexc7d286d61

53639408993 has 2 divisors, whose sum is σ = 53639408994. Its totient is φ = 53639408992.

The previous prime is 53639408923. The next prime is 53639409041. The reversal of 53639408993 is 39980493635.

53639408993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 53607067024 + 32341969 = 231532^2 + 5687^2 .

It is a cyclic number.

It is not a de Polignac number, because 53639408993 - 28 = 53639408737 is a prime.

It is not a weakly prime, because it can be changed into another prime (53639408923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26819704496 + 26819704497.

It is an arithmetic number, because the mean of its divisors is an integer number (26819704497).

Almost surely, 253639408993 is an apocalyptic number.

It is an amenable number.

53639408993 is a deficient number, since it is larger than the sum of its proper divisors (1).

53639408993 is an equidigital number, since it uses as much as digits as its factorization.

53639408993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18895680, while the sum is 59.

The spelling of 53639408993 in words is "fifty-three billion, six hundred thirty-nine million, four hundred eight thousand, nine hundred ninety-three".