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5364000662153 = 73794951218117
BaseRepresentation
bin100111000001110011101…
…0110101010001010001001
3200222210102102120122122212
41032003213112222022021
51200340433132142103
615224104325554505
71062351636224330
oct116034726521211
920883372518585
105364000662153
111788950597581
127276b4b75a35
132cba91443c63
14147894824d17
15947e39897d8
hex4e0e75aa289

5364000662153 has 16 divisors (see below), whose sum is σ = 6296065062144. Its totient is φ = 4473384667200.

The previous prime is 5364000662149. The next prime is 5364000662197. The reversal of 5364000662153 is 3512660004635.

It is a cyclic number.

It is not a de Polignac number, because 5364000662153 - 22 = 5364000662149 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5364000662153.

It is not an unprimeable number, because it can be changed into a prime (5364000662123) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24483251 + ... + 24701367.

It is an arithmetic number, because the mean of its divisors is an integer number (393504066384).

Almost surely, 25364000662153 is an apocalyptic number.

It is an amenable number.

5364000662153 is a deficient number, since it is larger than the sum of its proper divisors (932064399991).

5364000662153 is a wasteful number, since it uses less digits than its factorization.

5364000662153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 313112.

The product of its (nonzero) digits is 388800, while the sum is 41.

Adding to 5364000662153 its reverse (3512660004635), we get a palindrome (8876660666788).

The spelling of 5364000662153 in words is "five trillion, three hundred sixty-four billion, six hundred sixty-two thousand, one hundred fifty-three".

Divisors: 1 7 37 259 94951 218117 664657 1526819 3513187 8070329 24592309 56492303 20710427267 144972990869 766285808879 5364000662153