Base | Representation |
---|---|
bin | 11000011001001100110111… |
… | …00111000010001001100001 |
3 | 21000221011120002002220111001 |
4 | 30030212123213002021201 |
5 | 24012334223024320031 |
6 | 310031001001352001 |
7 | 14204353045325224 |
oct | 1414463347021141 |
9 | 230834502086431 |
10 | 53642457260641 |
11 | 16101702738717 |
12 | 6024326498601 |
13 | 23c16010796c2 |
14 | d364474395bb |
15 | 63056b7e0861 |
hex | 30c99b9c2261 |
53642457260641 has 2 divisors, whose sum is σ = 53642457260642. Its totient is φ = 53642457260640.
The previous prime is 53642457260611. The next prime is 53642457260701. The reversal of 53642457260641 is 14606275424635.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 53408398691025 + 234058569616 = 7308105^2 + 483796^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53642457260641 is a prime.
It is not a weakly prime, because it can be changed into another prime (53642457260611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26821228630320 + 26821228630321.
It is an arithmetic number, because the mean of its divisors is an integer number (26821228630321).
Almost surely, 253642457260641 is an apocalyptic number.
It is an amenable number.
53642457260641 is a deficient number, since it is larger than the sum of its proper divisors (1).
53642457260641 is an equidigital number, since it uses as much as digits as its factorization.
53642457260641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29030400, while the sum is 55.
The spelling of 53642457260641 in words is "fifty-three trillion, six hundred forty-two billion, four hundred fifty-seven million, two hundred sixty thousand, six hundred forty-one".
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