Base | Representation |
---|---|
bin | 110001111110000001… |
… | …110001010000101001 |
3 | 12010111020110122020102 |
4 | 301332001301100221 |
5 | 1334340411010211 |
6 | 40352011235145 |
7 | 3606411323651 |
oct | 617601612051 |
9 | 163436418212 |
10 | 53654000681 |
11 | 20833314926 |
12 | a494748ab5 |
13 | 50a0aa91c8 |
14 | 284db39361 |
15 | 15e0571a3b |
hex | c7e071429 |
53654000681 has 2 divisors, whose sum is σ = 53654000682. Its totient is φ = 53654000680.
The previous prime is 53654000671. The next prime is 53654000689. The reversal of 53654000681 is 18600045635.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 26828802025 + 26825198656 = 163795^2 + 163784^2 .
It is a cyclic number.
It is not a de Polignac number, because 53654000681 - 222 = 53649806377 is a prime.
It is a super-2 number, since 2×536540006812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53654000689) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26827000340 + 26827000341.
It is an arithmetic number, because the mean of its divisors is an integer number (26827000341).
Almost surely, 253654000681 is an apocalyptic number.
It is an amenable number.
53654000681 is a deficient number, since it is larger than the sum of its proper divisors (1).
53654000681 is an equidigital number, since it uses as much as digits as its factorization.
53654000681 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 38.
The spelling of 53654000681 in words is "fifty-three billion, six hundred fifty-four million, six hundred eighty-one", and thus it is an aban number.
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