Base | Representation |
---|---|
bin | 111101000000010111111001… |
… | …1011011110001111110001001 |
3 | 2121100222200221211101000101221 |
4 | 1322000233303123301332021 |
5 | 1030313331412301003001 |
6 | 5141140335504442041 |
7 | 221013003313652353 |
oct | 17200576333617611 |
9 | 2540880854330357 |
10 | 536613003141001 |
11 | 145a8832988a096 |
12 | 50227241019321 |
13 | 1a056509a217a7 |
14 | 96722ca7c20d3 |
15 | 4208807d501a1 |
hex | 1e80bf36f1f89 |
536613003141001 has 2 divisors, whose sum is σ = 536613003141002. Its totient is φ = 536613003141000.
The previous prime is 536613003140993. The next prime is 536613003141079. The reversal of 536613003141001 is 100141300316635.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 409426936958601 + 127186066182400 = 20234301^2 + 11277680^2 .
It is a cyclic number.
It is not a de Polignac number, because 536613003141001 - 23 = 536613003140993 is a prime.
It is not a weakly prime, because it can be changed into another prime (536613003141701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 268306501570500 + 268306501570501.
It is an arithmetic number, because the mean of its divisors is an integer number (268306501570501).
Almost surely, 2536613003141001 is an apocalyptic number.
It is an amenable number.
536613003141001 is a deficient number, since it is larger than the sum of its proper divisors (1).
536613003141001 is an equidigital number, since it uses as much as digits as its factorization.
536613003141001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 34.
Adding to 536613003141001 its reverse (100141300316635), we get a palindrome (636754303457636).
The spelling of 536613003141001 in words is "five hundred thirty-six trillion, six hundred thirteen billion, three million, one hundred forty-one thousand, one".
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