Base | Representation |
---|---|
bin | 1111100111100010010… |
… | …00100111100110110101 |
3 | 1220022010002001100001002 |
4 | 13303301020213212311 |
5 | 32243000101410031 |
6 | 1050304233213045 |
7 | 53524660413260 |
oct | 7636110474665 |
9 | 1808102040032 |
10 | 536621513141 |
11 | 19764194433a |
12 | 88001561185 |
13 | 3b7ac29a58c |
14 | 1bd88c23cd7 |
15 | de5ac11ccb |
hex | 7cf12279b5 |
536621513141 has 16 divisors (see below), whose sum is σ = 626845395456. Its totient is φ = 449804645376.
The previous prime is 536621513123. The next prime is 536621513173. The reversal of 536621513141 is 141315126635.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-536621513141 is a prime.
It is a super-3 number, since 3×5366215131413 (a number of 36 digits) contains 333 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 536621513095 and 536621513104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (536621513111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 269726 + ... + 1070511.
It is an arithmetic number, because the mean of its divisors is an integer number (39177837216).
Almost surely, 2536621513141 is an apocalyptic number.
It is an amenable number.
536621513141 is a deficient number, since it is larger than the sum of its proper divisors (90223882315).
536621513141 is a wasteful number, since it uses less digits than its factorization.
536621513141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1341508.
The product of its digits is 64800, while the sum is 38.
Adding to 536621513141 its reverse (141315126635), we get a palindrome (677936639776).
The spelling of 536621513141 in words is "five hundred thirty-six billion, six hundred twenty-one million, five hundred thirteen thousand, one hundred forty-one".
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