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53697213381601 = 121014437419501
BaseRepresentation
bin11000011010110010110110…
…10101000011101111100001
321001010101220010102001112001
430031121123111003233201
524014233343111202401
6310112054223204001
714211332001555646
oct1415313325035741
9231111803361461
1053697213381601
1116122951085849
126032a68146601
1323c681929968a
14d38d5d6a5dcd
15631bc39b6601
hex30d65b543be1

53697213381601 has 4 divisors (see below), whose sum is σ = 53701650813204. Its totient is φ = 53692775950000.

The previous prime is 53697213381599. The next prime is 53697213381607. The reversal of 53697213381601 is 10618331279635.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 46258769904400 + 7438443477201 = 6801380^2 + 2727351^2 .

It is a cyclic number.

It is not a de Polignac number, because 53697213381601 - 21 = 53697213381599 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53697213381607) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2218697650 + ... + 2218721851.

It is an arithmetic number, because the mean of its divisors is an integer number (13425412703301).

Almost surely, 253697213381601 is an apocalyptic number.

It is an amenable number.

53697213381601 is a deficient number, since it is larger than the sum of its proper divisors (4437431603).

53697213381601 is a wasteful number, since it uses less digits than its factorization.

53697213381601 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4437431602.

The product of its (nonzero) digits is 4898880, while the sum is 55.

The spelling of 53697213381601 in words is "fifty-three trillion, six hundred ninety-seven billion, two hundred thirteen million, three hundred eighty-one thousand, six hundred one".

Divisors: 1 12101 4437419501 53697213381601