Base | Representation |
---|---|
bin | 110010000000110010… |
… | …001100111000001011 |
3 | 12010121110111101221122 |
4 | 302000302030320023 |
5 | 1334434231014042 |
6 | 40400342425455 |
7 | 3610512413654 |
oct | 620062147013 |
9 | 163543441848 |
10 | 53700251147 |
11 | 20857434554 |
12 | a4a813228b |
13 | 50aa550a4a |
14 | 2855d3852b |
15 | 15e465a7d2 |
hex | c80c8ce0b |
53700251147 has 2 divisors, whose sum is σ = 53700251148. Its totient is φ = 53700251146.
The previous prime is 53700251081. The next prime is 53700251183. The reversal of 53700251147 is 74115200735.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53700251147 - 218 = 53699989003 is a prime.
It is not a weakly prime, because it can be changed into another prime (53700251447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26850125573 + 26850125574.
It is an arithmetic number, because the mean of its divisors is an integer number (26850125574).
Almost surely, 253700251147 is an apocalyptic number.
53700251147 is a deficient number, since it is larger than the sum of its proper divisors (1).
53700251147 is an equidigital number, since it uses as much as digits as its factorization.
53700251147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29400, while the sum is 35.
The spelling of 53700251147 in words is "fifty-three billion, seven hundred million, two hundred fifty-one thousand, one hundred forty-seven".
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