53700407113134 has 16 divisors (see below), whose sum is σ = 107576019477072. Its totient is φ = 17870934829248.

The previous prime is 53700407113127. The next prime is 53700407113189. The reversal of 53700407113134 is 43131170400735.

It is a super-3 number, since 3×53700407113134³ (a number of 42 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53700407113092 and 53700407113101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7300214799 + ... + 7300222154.

It is an arithmetic number, because the mean of its divisors is an integer number (6723501217317).

Almost surely, 2^{53700407113134} is an apocalyptic number.

53700407113134 is an abundant number, since it is smaller than the sum of its proper divisors (53875612363938).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53700407113134 is a wasteful number, since it uses less digits than its factorization.

53700407113134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14600437571.

The product of its (nonzero) digits is 105840, while the sum is 39.

Adding to 53700407113134 its reverse (43131170400735), we get a palindrome (96831577513869).

The spelling of 53700407113134 in words is "fifty-three trillion, seven hundred billion, four hundred seven million, one hundred thirteen thousand, one hundred thirty-four".