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5370504803 is a prime number
BaseRepresentation
bin1010000000001101…
…10110011001100011
3111212021112220121022
411000012312121203
541444322123203
62244524320055
7250041352256
oct50006663143
914767486538
105370504803
112306567824
12105a6a302b
13677843bc1
1438d38909d
15216740a38
hex1401b6663

5370504803 has 2 divisors, whose sum is σ = 5370504804. Its totient is φ = 5370504802.

The previous prime is 5370504779. The next prime is 5370504817. The reversal of 5370504803 is 3084050735.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5370504803 - 28 = 5370504547 is a prime.

It is not a weakly prime, because it can be changed into another prime (5370504103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2685252401 + 2685252402.

It is an arithmetic number, because the mean of its divisors is an integer number (2685252402).

Almost surely, 25370504803 is an apocalyptic number.

5370504803 is a deficient number, since it is larger than the sum of its proper divisors (1).

5370504803 is an equidigital number, since it uses as much as digits as its factorization.

5370504803 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50400, while the sum is 35.

The square root of 5370504803 is about 73283.7280915757. The cubic root of 5370504803 is about 1751.2105695198.

The spelling of 5370504803 in words is "five billion, three hundred seventy million, five hundred four thousand, eight hundred three".