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5371505153 = 72543301753
BaseRepresentation
bin1010000000010101…
…01010101000000001
3111212100102201211022
411000022222220001
542000101131103
62245001555225
7250053016610
oct50012525001
914770381738
105371505153
112307090363
12105aaa5b15
13677b04321
1438d569877
1521688c138
hex1402aaa01

5371505153 has 8 divisors (see below), whose sum is σ = 6141297408. Its totient is φ = 4602321504.

The previous prime is 5371505137. The next prime is 5371505189. The reversal of 5371505153 is 3515051735.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5371505153 - 24 = 5371505137 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5371525153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 133076 + ... + 168677.

It is an arithmetic number, because the mean of its divisors is an integer number (767662176).

Almost surely, 25371505153 is an apocalyptic number.

It is an amenable number.

5371505153 is a deficient number, since it is larger than the sum of its proper divisors (769792255).

5371505153 is a wasteful number, since it uses less digits than its factorization.

5371505153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 304303.

The product of its (nonzero) digits is 39375, while the sum is 35.

The square root of 5371505153 is about 73290.5529587545. The cubic root of 5371505153 is about 1751.3192939197.

Adding to 5371505153 its reverse (3515051735), we get a palindrome (8886556888).

The spelling of 5371505153 in words is "five billion, three hundred seventy-one million, five hundred five thousand, one hundred fifty-three".

Divisors: 1 7 2543 17801 301753 2112271 767357879 5371505153