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53749213313 is a prime number
BaseRepresentation
bin110010000011101100…
…111110100010000001
312010201212121221102012
4302003230332202001
51340034244311223
640405252102305
73611645526545
oct620354764201
9163655557365
1053749213313
1120882036554
12a500604995
1350b7734943
14285c641a25
1515e8accc78
hexc83b3e881

53749213313 has 2 divisors, whose sum is σ = 53749213314. Its totient is φ = 53749213312.

The previous prime is 53749213279. The next prime is 53749213387. The reversal of 53749213313 is 31331294735.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29821145344 + 23928067969 = 172688^2 + 154687^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53749213313 is a prime.

It is a super-3 number, since 3×537492133133 (a number of 33 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (53749213393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26874606656 + 26874606657.

It is an arithmetic number, because the mean of its divisors is an integer number (26874606657).

Almost surely, 253749213313 is an apocalyptic number.

It is an amenable number.

53749213313 is a deficient number, since it is larger than the sum of its proper divisors (1).

53749213313 is an equidigital number, since it uses as much as digits as its factorization.

53749213313 is an evil number, because the sum of its binary digits is even.

The product of its digits is 204120, while the sum is 41.

The spelling of 53749213313 in words is "fifty-three billion, seven hundred forty-nine million, two hundred thirteen thousand, three hundred thirteen".