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53755017745441 = 54799399809419
BaseRepresentation
bin11000011100011110100001…
…01111001101010000100001
321001022221002121111222200111
430032033100233031100201
524021210234020323231
6310154414135251321
714215446310551025
oct1416172057152041
9231287077458614
1053755017745441
1116145414143971
1260420ba819b41
1323cc0cbb9256c
14d3ba846d6385
156334585b04b1
hex30e3d0bcd421

53755017745441 has 4 divisors (see below), whose sum is σ = 53755033034800. Its totient is φ = 53755002456084.

The previous prime is 53755017745367. The next prime is 53755017745621. The reversal of 53755017745441 is 14454771055735.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 53755017745441 - 219 = 53755017221153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53755017745141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 575230 + ... + 10384648.

It is an arithmetic number, because the mean of its divisors is an integer number (13438758258700).

Almost surely, 253755017745441 is an apocalyptic number.

It is an amenable number.

53755017745441 is a deficient number, since it is larger than the sum of its proper divisors (15289359).

53755017745441 is an equidigital number, since it uses as much as digits as its factorization.

53755017745441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15289358.

The product of its (nonzero) digits is 41160000, while the sum is 58.

The spelling of 53755017745441 in words is "fifty-three trillion, seven hundred fifty-five billion, seventeen million, seven hundred forty-five thousand, four hundred forty-one".

Divisors: 1 5479939 9809419 53755017745441