Base | Representation |
---|---|
bin | 11000011101000100001110… |
… | …00101111100111111110001 |
3 | 21001101212100010022012112001 |
4 | 30032202013011330333301 |
5 | 24022023211244440031 |
6 | 310212002333334001 |
7 | 14220063666622306 |
oct | 1416420705747761 |
9 | 231355303265461 |
10 | 53775257030641 |
11 | 16152a5a748453 |
12 | 6046008937301 |
13 | 2400ca5cca873 |
14 | d3ca446a90ad |
15 | 633c40345861 |
hex | 30e88717cff1 |
53775257030641 has 2 divisors, whose sum is σ = 53775257030642. Its totient is φ = 53775257030640.
The previous prime is 53775257030611. The next prime is 53775257030683. The reversal of 53775257030641 is 14603075257735.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 39811052160000 + 13964204870641 = 6309600^2 + 3736871^2 .
It is a cyclic number.
It is not a de Polignac number, because 53775257030641 - 223 = 53775248642033 is a prime.
It is not a weakly prime, because it can be changed into another prime (53775257030611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26887628515320 + 26887628515321.
It is an arithmetic number, because the mean of its divisors is an integer number (26887628515321).
Almost surely, 253775257030641 is an apocalyptic number.
It is an amenable number.
53775257030641 is a deficient number, since it is larger than the sum of its proper divisors (1).
53775257030641 is an equidigital number, since it uses as much as digits as its factorization.
53775257030641 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18522000, while the sum is 55.
The spelling of 53775257030641 in words is "fifty-three trillion, seven hundred seventy-five billion, two hundred fifty-seven million, thirty thousand, six hundred forty-one".
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