5384149753 has 4 divisors (see below), whose sum is σ = 5384301220. Its totient is φ = 5383998288.

The previous prime is 5384149751. The next prime is 5384149777. The reversal of 5384149753 is 3579414835.

5384149753 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 4997358864 + 386790889 = 70692^2 + 19667^2 .

It is a cyclic number.

It is not a de Polignac number, because 5384149753 - 2¹ = 5384149751 is a prime.

It is a super-2 number, since 2×5384149753² = 57978137125459922018, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5384149697 and 5384149706.

It is not an unprimeable number, because it can be changed into a prime (5384149751) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9751 + ... + 104227.

It is an arithmetic number, because the mean of its divisors is an integer number (1346075305).

Almost surely, 2^5384149753 is an apocalyptic number.

It is an amenable number.

5384149753 is a deficient number, since it is larger than the sum of its proper divisors (151467).

5384149753 is an equidigital number, since it uses as much as digits as its factorization.

5384149753 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 151466.

The product of its digits is 1814400, while the sum is 49.

The square root of 5384149753 is about 73376.7657572886. The cubic root of 5384149753 is about 1752.6924272510.

The spelling of 5384149753 in words is "five billion, three hundred eighty-four million, one hundred forty-nine thousand, seven hundred fifty-three".