Base | Representation |
---|---|
bin | 110010001001001111… |
… | …001011010101110001 |
3 | 12010222100100021122102 |
4 | 302021033023111301 |
5 | 1340232032033003 |
6 | 40422410150145 |
7 | 3614153666501 |
oct | 621117132561 |
9 | 163870307572 |
10 | 53842064753 |
11 | 2091a495184 |
12 | a527722355 |
13 | 5100a44719 |
14 | 286aad1a01 |
15 | 1601d1e588 |
hex | c893cb571 |
53842064753 has 2 divisors, whose sum is σ = 53842064754. Its totient is φ = 53842064752.
The previous prime is 53842064741. The next prime is 53842064761. The reversal of 53842064753 is 35746024835.
53842064753 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53226181264 + 615883489 = 230708^2 + 24817^2 .
It is a cyclic number.
It is not a de Polignac number, because 53842064753 - 226 = 53774955889 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53842064698 and 53842064707.
It is not a weakly prime, because it can be changed into another prime (53842064713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26921032376 + 26921032377.
It is an arithmetic number, because the mean of its divisors is an integer number (26921032377).
Almost surely, 253842064753 is an apocalyptic number.
It is an amenable number.
53842064753 is a deficient number, since it is larger than the sum of its proper divisors (1).
53842064753 is an equidigital number, since it uses as much as digits as its factorization.
53842064753 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2419200, while the sum is 47.
The spelling of 53842064753 in words is "fifty-three billion, eight hundred forty-two million, sixty-four thousand, seven hundred fifty-three".
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