Base | Representation |
---|---|
bin | 11000011111010000100001… |
… | …01110010001111111001011 |
3 | 21001200001202112202011210111 |
4 | 30033220100232101333023 |
5 | 24024241442103300003 |
6 | 310310340513255151 |
7 | 14225401405020553 |
oct | 1417502056217713 |
9 | 231601675664714 |
10 | 53850580525003 |
11 | 161819a2908639 |
12 | 605872a5644b7 |
13 | 240811b309682 |
14 | d4254c310163 |
15 | 635b9ceace6d |
hex | 30fa10b91fcb |
53850580525003 has 8 divisors (see below), whose sum is σ = 54867589358400. Its totient is φ = 52833607252608.
The previous prime is 53850580524991. The next prime is 53850580525019. The reversal of 53850580525003 is 30052508505835.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53850580525003 - 229 = 53850043654091 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53850580525033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5823123 + ... + 11899996.
It is an arithmetic number, because the mean of its divisors is an integer number (6858448669800).
Almost surely, 253850580525003 is an apocalyptic number.
53850580525003 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
53850580525003 is a deficient number, since it is larger than the sum of its proper divisors (1017008833397).
53850580525003 is a wasteful number, since it uses less digits than its factorization.
53850580525003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17780501.
The product of its (nonzero) digits is 3600000, while the sum is 49.
The spelling of 53850580525003 in words is "fifty-three trillion, eight hundred fifty billion, five hundred eighty million, five hundred twenty-five thousand, three".
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