Base | Representation |
---|---|
bin | 11000011111110010010010… |
… | …00001101110110101110011 |
3 | 21001201210112200011210000101 |
4 | 30033321021001232311303 |
5 | 24030041101441022303 |
6 | 310322535204133231 |
7 | 14226612504453646 |
oct | 1417711101566563 |
9 | 231653480153011 |
10 | 53868705017203 |
11 | 1618965369a90a |
12 | 6060148397217 |
13 | 2409a4927777b |
14 | d4338b4a5a5d |
15 | 6363ae257d1d |
hex | 30fe4906ed73 |
53868705017203 has 2 divisors, whose sum is σ = 53868705017204. Its totient is φ = 53868705017202.
The previous prime is 53868705017177. The next prime is 53868705017209. The reversal of 53868705017203 is 30271050786835.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53868705017203 - 229 = 53868168146291 is a prime.
It is a super-3 number, since 3×538687050172033 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (53868705017209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26934352508601 + 26934352508602.
It is an arithmetic number, because the mean of its divisors is an integer number (26934352508602).
Almost surely, 253868705017203 is an apocalyptic number.
53868705017203 is a deficient number, since it is larger than the sum of its proper divisors (1).
53868705017203 is an equidigital number, since it uses as much as digits as its factorization.
53868705017203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8467200, while the sum is 55.
The spelling of 53868705017203 in words is "fifty-three trillion, eight hundred sixty-eight billion, seven hundred five million, seventeen thousand, two hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •