Base | Representation |
---|---|
bin | 110010001010111110… |
… | …110100100001101001 |
3 | 12011001101102011222112 |
4 | 302022332310201221 |
5 | 1340312030101213 |
6 | 40425333332105 |
7 | 3614660522213 |
oct | 621276644151 |
9 | 164041364875 |
10 | 53871331433 |
11 | 20934a64717 |
12 | a535497035 |
13 | 5106b2099a |
14 | 287094d5b3 |
15 | 16046a0ea8 |
hex | c8afb4869 |
53871331433 has 18 divisors (see below), whose sum is σ = 58508004042. Its totient is φ = 49429757440.
The previous prime is 53871331417. The next prime is 53871331439. The reversal of 53871331433 is 33413317835.
53871331433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 9 ways, for example, as 928542784 + 52942788649 = 30472^2 + 230093^2 .
It is not a de Polignac number, because 53871331433 - 24 = 53871331417 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (41).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53871331439) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 39235535 + ... + 39236907.
It is an arithmetic number, because the mean of its divisors is an integer number (3250444669).
Almost surely, 253871331433 is an apocalyptic number.
It is an amenable number.
53871331433 is a deficient number, since it is larger than the sum of its proper divisors (4636672609).
53871331433 is an frugal number, since it uses more digits than its factorization.
53871331433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2845 (or 1431 counting only the distinct ones).
The product of its digits is 272160, while the sum is 41.
The spelling of 53871331433 in words is "fifty-three billion, eight hundred seventy-one million, three hundred thirty-one thousand, four hundred thirty-three".
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