Base | Representation |
---|---|
bin | 110010001011101100… |
… | …101101011010010001 |
3 | 12011002020001100022211 |
4 | 302023230231122101 |
5 | 1340323120022123 |
6 | 40430443232121 |
7 | 3615165003454 |
oct | 621354553221 |
9 | 164066040284 |
10 | 53883360913 |
11 | 20940830638 |
12 | a539518641 |
13 | 5109473215 |
14 | 28723a149b |
15 | 160577a40d |
hex | c8bb2d691 |
53883360913 has 4 divisors (see below), whose sum is σ = 53888601088. Its totient is φ = 53878120740.
The previous prime is 53883360907. The next prime is 53883360917. The reversal of 53883360913 is 31906338835.
53883360913 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53883360913 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53883360917) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2604633 + ... + 2625238.
It is an arithmetic number, because the mean of its divisors is an integer number (13472150272).
Almost surely, 253883360913 is an apocalyptic number.
It is an amenable number.
53883360913 is a deficient number, since it is larger than the sum of its proper divisors (5240175).
53883360913 is a wasteful number, since it uses less digits than its factorization.
53883360913 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5240174.
The product of its (nonzero) digits is 1399680, while the sum is 49.
The spelling of 53883360913 in words is "fifty-three billion, eight hundred eighty-three million, three hundred sixty thousand, nine hundred thirteen".
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