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53890866433 = 167322699799
BaseRepresentation
bin110010001100001001…
…010101110100000001
312011002202011122222001
4302030021111310001
51340332030211213
640431312144001
73615315543445
oct621411256401
9164082148861
1053890866433
1120944a97648
12a53bb38001
13510aba0561
142873396825
15160625e1dd
hexc8c255d01

53890866433 has 4 divisors (see below), whose sum is σ = 54213566400. Its totient is φ = 53568166468.

The previous prime is 53890866389. The next prime is 53890866443. The reversal of 53890866433 is 33466809835.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53890866433 - 217 = 53890735361 is a prime.

It is a super-2 number, since 2×538908664332 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53890866443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 161349733 + ... + 161350066.

It is an arithmetic number, because the mean of its divisors is an integer number (13553391600).

Almost surely, 253890866433 is an apocalyptic number.

It is an amenable number.

53890866433 is a deficient number, since it is larger than the sum of its proper divisors (322699967).

53890866433 is a wasteful number, since it uses less digits than its factorization.

53890866433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 322699966.

The product of its (nonzero) digits is 11197440, while the sum is 55.

The spelling of 53890866433 in words is "fifty-three billion, eight hundred ninety million, eight hundred sixty-six thousand, four hundred thirty-three".

Divisors: 1 167 322699799 53890866433