Base | Representation |
---|---|
bin | 100111001111110101011… |
… | …0001101110000100110011 |
3 | 201002200011200210210022211 |
4 | 1032133222301232010303 |
5 | 1201334130422440203 |
6 | 15250005325112551 |
7 | 1064466251533540 |
oct | 116375261560463 |
9 | 21080150723284 |
10 | 5394122858803 |
11 | 179a6a8802778 |
12 | 7315009b8757 |
13 | 301881c21a63 |
14 | 14911119bbc7 |
15 | 954a819ec6d |
hex | 4e7eac6e133 |
5394122858803 has 4 divisors (see below), whose sum is σ = 6164711838640. Its totient is φ = 4623533878968.
The previous prime is 5394122858759. The next prime is 5394122858827. The reversal of 5394122858803 is 3088582214935.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5394122858803 - 241 = 3195099603251 is a prime.
It is a super-2 number, since 2×53941228588032 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5394122858603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385294489908 + ... + 385294489921.
It is an arithmetic number, because the mean of its divisors is an integer number (1541177959660).
Almost surely, 25394122858803 is an apocalyptic number.
5394122858803 is a deficient number, since it is larger than the sum of its proper divisors (770588979837).
5394122858803 is an equidigital number, since it uses as much as digits as its factorization.
5394122858803 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 770588979836.
The product of its (nonzero) digits is 16588800, while the sum is 58.
The spelling of 5394122858803 in words is "five trillion, three hundred ninety-four billion, one hundred twenty-two million, eight hundred fifty-eight thousand, eight hundred three".
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