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540035000502233 is a prime number
BaseRepresentation
bin111101011001010001011001…
…0010111110000011111011001
32121211002211201201010101121112
41322302202302113300133121
51031240413140112032413
65152320353200150105
7221515145513416115
oct17262426227603731
92554084651111545
10540035000502233
11147087615111245
125069a499008335
131a24410b2c98b2
14974db95132745
15426783a2492a8
hex1eb28b25f07d9

540035000502233 has 2 divisors, whose sum is σ = 540035000502234. Its totient is φ = 540035000502232.

The previous prime is 540035000502133. The next prime is 540035000502287. The reversal of 540035000502233 is 332205000530045.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 521863093328329 + 18171907173904 = 22844323^2 + 4262852^2 .

It is a cyclic number.

It is not a de Polignac number, because 540035000502233 - 216 = 540035000436697 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 540035000502233.

It is not a weakly prime, because it can be changed into another prime (540035000502133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270017500251116 + 270017500251117.

It is an arithmetic number, because the mean of its divisors is an integer number (270017500251117).

Almost surely, 2540035000502233 is an apocalyptic number.

It is an amenable number.

540035000502233 is a deficient number, since it is larger than the sum of its proper divisors (1).

540035000502233 is an equidigital number, since it uses as much as digits as its factorization.

540035000502233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54000, while the sum is 32.

The spelling of 540035000502233 in words is "five hundred forty trillion, thirty-five billion, five hundred two thousand, two hundred thirty-three".