Base | Representation |
---|---|
bin | 11000100011101110111001… |
… | …00100110100010001101001 |
3 | 21002012202121020001212012220 |
4 | 30101313130210310101221 |
5 | 24034301324024421213 |
6 | 310505124423224253 |
7 | 14242453334566326 |
oct | 1421673444642151 |
9 | 232182536055186 |
10 | 54004324451433 |
11 | 16231118299064 |
12 | 6082496ba8089 |
13 | 241978041c4c5 |
14 | d49b74dd7b4d |
15 | 639b9a5cde23 |
hex | 311ddc934469 |
54004324451433 has 8 divisors (see below), whose sum is σ = 72237295730496. Its totient is φ = 35887118070000.
The previous prime is 54004324451383. The next prime is 54004324451443. The reversal of 54004324451433 is 33415442340045.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 54004324451433 - 218 = 54004324189289 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (54004324451443) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28941223318 + ... + 28941225183.
It is an arithmetic number, because the mean of its divisors is an integer number (9029661966312).
Almost surely, 254004324451433 is an apocalyptic number.
It is an amenable number.
54004324451433 is a deficient number, since it is larger than the sum of its proper divisors (18232971279063).
54004324451433 is a wasteful number, since it uses less digits than its factorization.
54004324451433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57882448815.
The product of its (nonzero) digits is 1382400, while the sum is 42.
Adding to 54004324451433 its reverse (33415442340045), we get a palindrome (87419766791478).
The spelling of 54004324451433 in words is "fifty-four trillion, four billion, three hundred twenty-four million, four hundred fifty-one thousand, four hundred thirty-three".
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