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5401301131 is a prime number
BaseRepresentation
bin1010000011111000…
…10101000010001011
3111221102111112020001
411001330111002023
542030213114011
62251544343431
7250564205422
oct50174250213
914842445201
105401301131
112321991536
121068a74b77
13681037495
143934c42b9
152192c57c1
hex141f1508b

5401301131 has 2 divisors, whose sum is σ = 5401301132. Its totient is φ = 5401301130.

The previous prime is 5401301123. The next prime is 5401301137. The reversal of 5401301131 is 1311031045.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5401301131 - 23 = 5401301123 is a prime.

It is a super-2 number, since 2×54013011312 = 58348107815483758322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5401301099 and 5401301108.

It is not a weakly prime, because it can be changed into another prime (5401301137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2700650565 + 2700650566.

It is an arithmetic number, because the mean of its divisors is an integer number (2700650566).

Almost surely, 25401301131 is an apocalyptic number.

5401301131 is a deficient number, since it is larger than the sum of its proper divisors (1).

5401301131 is an equidigital number, since it uses as much as digits as its factorization.

5401301131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 5401301131 is about 73493.5448253791. The cubic root of 5401301131 is about 1754.5515401350.

Adding to 5401301131 its reverse (1311031045), we get a palindrome (6712332176).

The spelling of 5401301131 in words is "five billion, four hundred one million, three hundred one thousand, one hundred thirty-one".