Base | Representation |
---|---|
bin | 110010010011100000… |
… | …100110001000101010 |
3 | 12011102100121222102200 |
4 | 302103200212020222 |
5 | 1341110141344424 |
6 | 40451444041030 |
7 | 3621345564630 |
oct | 622340461052 |
9 | 164370558380 |
10 | 54014403114 |
11 | 209a87a4581 |
12 | a575393176 |
13 | 512a665199 |
14 | 2885953350 |
15 | 16120128c9 |
hex | c9382622a |
54014403114 has 96 divisors (see below), whose sum is σ = 134757727104. Its totient is φ = 15316853760.
The previous prime is 54014403097. The next prime is 54014403133. The reversal of 54014403114 is 41130441045.
54014403114 is a `hidden beast` number, since 540 + 1 + 4 + 4 + 0 + 3 + 114 = 666.
It is a super-3 number, since 3×540144031143 (a number of 33 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 9501717 + ... + 9507399.
It is an arithmetic number, because the mean of its divisors is an integer number (1403726324).
Almost surely, 254014403114 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 54014403114, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (67378863552).
54014403114 is an abundant number, since it is smaller than the sum of its proper divisors (80743323990).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
54014403114 is a wasteful number, since it uses less digits than its factorization.
54014403114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6252 (or 6249 counting only the distinct ones).
The product of its (nonzero) digits is 3840, while the sum is 27.
Adding to 54014403114 its reverse (41130441045), we get a palindrome (95144844159).
The spelling of 54014403114 in words is "fifty-four billion, fourteen million, four hundred three thousand, one hundred fourteen".
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