Base | Representation |
---|---|
bin | 110010010011100011… |
… | …111010010001001011 |
3 | 12011102102021010100001 |
4 | 302103203322101023 |
5 | 1341110402201021 |
6 | 40451514423431 |
7 | 3621356144101 |
oct | 622343722113 |
9 | 164372233301 |
10 | 54015272011 |
11 | 209a9238378 |
12 | a575731b77 |
13 | 512a8aa81c |
14 | 2885adbc71 |
15 | 1612135091 |
hex | c938fa44b |
54015272011 has 4 divisors (see below), whose sum is σ = 54016837024. Its totient is φ = 54013707000.
The previous prime is 54015271993. The next prime is 54015272027. The reversal of 54015272011 is 11027251045.
54015272011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54015272011 - 25 = 54015271979 is a prime.
It is a super-2 number, since 2×540152720112 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54015270011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 729540 + ... + 800161.
It is an arithmetic number, because the mean of its divisors is an integer number (13504209256).
Almost surely, 254015272011 is an apocalyptic number.
54015272011 is a deficient number, since it is larger than the sum of its proper divisors (1565013).
54015272011 is a wasteful number, since it uses less digits than its factorization.
54015272011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1565012.
The product of its (nonzero) digits is 2800, while the sum is 28.
The spelling of 54015272011 in words is "fifty-four billion, fifteen million, two hundred seventy-two thousand, eleven".
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