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5401747103153 is a prime number
BaseRepresentation
bin100111010011011000100…
…1101111001110110110001
3201010101212001011112101012
41032212301031321312301
51202000234224300103
615253310043120305
71065156220536302
oct116466115716661
921111761145335
105401747103153
1117a2960464365
12732a8a213095
133024c866184b
141496359b27a9
15957a26c52d8
hex4e9b1379db1

5401747103153 has 2 divisors, whose sum is σ = 5401747103154. Its totient is φ = 5401747103152.

The previous prime is 5401747103083. The next prime is 5401747103161. The reversal of 5401747103153 is 3513017471045.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3310463803024 + 2091283300129 = 1819468^2 + 1446127^2 .

It is a cyclic number.

It is not a de Polignac number, because 5401747103153 - 212 = 5401747099057 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5401747103153.

It is not a weakly prime, because it can be changed into another prime (5401747183153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2700873551576 + 2700873551577.

It is an arithmetic number, because the mean of its divisors is an integer number (2700873551577).

Almost surely, 25401747103153 is an apocalyptic number.

It is an amenable number.

5401747103153 is a deficient number, since it is larger than the sum of its proper divisors (1).

5401747103153 is an equidigital number, since it uses as much as digits as its factorization.

5401747103153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 176400, while the sum is 41.

The spelling of 5401747103153 in words is "five trillion, four hundred one billion, seven hundred forty-seven million, one hundred three thousand, one hundred fifty-three".