Base | Representation |
---|---|
bin | 11000100100011111010010… |
… | …01001001101011011111010 |
3 | 21002022020122212021200012111 |
4 | 30102033221021031123322 |
5 | 24040213031102401132 |
6 | 310525102435202534 |
7 | 14244363220624564 |
oct | 1422175111153372 |
9 | 232266585250174 |
10 | 54030305122042 |
11 | 1624113a746467 |
12 | 6087527a4644a |
13 | 241c060b85a92 |
14 | d4b11b6da334 |
15 | 63a6bb415647 |
hex | 3123e924d6fa |
54030305122042 has 4 divisors (see below), whose sum is σ = 81045457683066. Its totient is φ = 27015152561020.
The previous prime is 54030305121941. The next prime is 54030305122049. The reversal of 54030305122042 is 24022150303045.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 38483300587081 + 15547004534961 = 6203491^2 + 3942969^2 .
It is a junction number, because it is equal to n+sod(n) for n = 54030305121995 and 54030305122013.
It is not an unprimeable number, because it can be changed into a prime (54030305122049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13507576280509 + ... + 13507576280512.
Almost surely, 254030305122042 is an apocalyptic number.
54030305122042 is a deficient number, since it is larger than the sum of its proper divisors (27015152561024).
54030305122042 is a wasteful number, since it uses less digits than its factorization.
54030305122042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27015152561023.
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 54030305122042 its reverse (24022150303045), we get a palindrome (78052455425087).
The spelling of 54030305122042 in words is "fifty-four trillion, thirty billion, three hundred five million, one hundred twenty-two thousand, forty-two".
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