Base | Representation |
---|---|
bin | 111101011011001110110011… |
… | …0101010101101010111011001 |
3 | 2121212001120212120202010112100 |
4 | 1322312131212222231113121 |
5 | 1031304321213203411101 |
6 | 5153044212553034013 |
7 | 221543461365654330 |
oct | 17266354652552731 |
9 | 2555046776663470 |
10 | 540304313341401 |
11 | 1471808551a43a4 |
12 | 507227193b5909 |
13 | 1a26362a59ac6b |
14 | 975cc22874d17 |
15 | 426e84d7e5e86 |
hex | 1eb6766aad5d9 |
540304313341401 has 48 divisors (see below), whose sum is σ = 922978339171200. Its totient is φ = 298004861113344.
The previous prime is 540304313341381. The next prime is 540304313341409. The reversal of 540304313341401 is 104143313403045.
540304313341401 is a `hidden beast` number, since 5 + 4 + 0 + 304 + 3 + 1 + 3 + 341 + 4 + 0 + 1 = 666.
It is not a de Polignac number, because 540304313341401 - 211 = 540304313339353 is a prime.
It is not an unprimeable number, because it can be changed into a prime (540304313341409) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 40870551 + ... + 52450076.
It is an arithmetic number, because the mean of its divisors is an integer number (19228715399400).
Almost surely, 2540304313341401 is an apocalyptic number.
It is an amenable number.
540304313341401 is a deficient number, since it is larger than the sum of its proper divisors (382674025829799).
540304313341401 is a wasteful number, since it uses less digits than its factorization.
540304313341401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93323838 (or 93323835 counting only the distinct ones).
The product of its (nonzero) digits is 103680, while the sum is 36.
Adding to 540304313341401 its reverse (104143313403045), we get a palindrome (644447626744446).
The spelling of 540304313341401 in words is "five hundred forty trillion, three hundred four billion, three hundred thirteen million, three hundred forty-one thousand, four hundred one".
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