Base | Representation |
---|---|
bin | 100111010100000001001… |
… | …1101000010000011110011 |
3 | 201010112101000202001111021 |
4 | 1032220002131002003303 |
5 | 1202011032131222121 |
6 | 15254053211200311 |
7 | 1065235050265612 |
oct | 116500235020363 |
9 | 21115330661437 |
10 | 5403110023411 |
11 | 17a349a827541 |
12 | 7331aa746097 |
13 | 302684b29a39 |
14 | 1497249d1879 |
15 | 95832193641 |
hex | 4ea027420f3 |
5403110023411 has 2 divisors, whose sum is σ = 5403110023412. Its totient is φ = 5403110023410.
The previous prime is 5403110023397. The next prime is 5403110023417. The reversal of 5403110023411 is 1143200113045.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5403110023411 - 239 = 4853354209523 is a prime.
It is not a weakly prime, because it can be changed into another prime (5403110023417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2701555011705 + 2701555011706.
It is an arithmetic number, because the mean of its divisors is an integer number (2701555011706).
Almost surely, 25403110023411 is an apocalyptic number.
5403110023411 is a deficient number, since it is larger than the sum of its proper divisors (1).
5403110023411 is an equidigital number, since it uses as much as digits as its factorization.
5403110023411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 5403110023411 its reverse (1143200113045), we get a palindrome (6546310136456).
The spelling of 5403110023411 in words is "five trillion, four hundred three billion, one hundred ten million, twenty-three thousand, four hundred eleven".
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