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540516213147721 is a prime number
BaseRepresentation
bin111101011100110001011110…
…0111000010100100001001001
32121212210211211020121121111011
41322321202330320110201021
51031321304201031211341
65153325415333203521
7221565002433415246
oct17271427470244111
92555724736547434
10540516213147721
11147252703103178
12507577b61905a1
131a27a5ca070c45
1497691a51325cd
1542751017e8b81
hex1eb98bce14849

540516213147721 has 2 divisors, whose sum is σ = 540516213147722. Its totient is φ = 540516213147720.

The previous prime is 540516213147709. The next prime is 540516213147769. The reversal of 540516213147721 is 127741312615045.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 459433031803321 + 81083181344400 = 21434389^2 + 9004620^2 .

It is a cyclic number.

It is not a de Polignac number, because 540516213147721 - 215 = 540516213114953 is a prime.

It is not a weakly prime, because it can be changed into another prime (540516213147221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270258106573860 + 270258106573861.

It is an arithmetic number, because the mean of its divisors is an integer number (270258106573861).

Almost surely, 2540516213147721 is an apocalyptic number.

It is an amenable number.

540516213147721 is a deficient number, since it is larger than the sum of its proper divisors (1).

540516213147721 is an equidigital number, since it uses as much as digits as its factorization.

540516213147721 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1411200, while the sum is 49.

The spelling of 540516213147721 in words is "five hundred forty trillion, five hundred sixteen billion, two hundred thirteen million, one hundred forty-seven thousand, seven hundred twenty-one".