Base | Representation |
---|---|
bin | 11000100101001011110110… |
… | …10111101000010101010011 |
3 | 21002101112102110012121012111 |
4 | 30102211323113220111103 |
5 | 24041111032200242433 |
6 | 310544101045210151 |
7 | 14246201201215525 |
oct | 1422457327502523 |
9 | 232345373177174 |
10 | 54054233212243 |
11 | 162502a9503820 |
12 | 60900a5400957 |
13 | 24213a52c5234 |
14 | d4c34b577a15 |
15 | 63b11be4edcd |
hex | 31297b5e8553 |
54054233212243 has 32 divisors (see below), whose sum is σ = 59218393006080. Its totient is φ = 48932271300000.
The previous prime is 54054233212181. The next prime is 54054233212283. The reversal of 54054233212243 is 34221233245045.
It is not a de Polignac number, because 54054233212243 - 213 = 54054233204051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54054233212196 and 54054233212205.
It is not an unprimeable number, because it can be changed into a prime (54054233212283) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10962121488 + ... + 10962126418.
It is an arithmetic number, because the mean of its divisors is an integer number (1850574781440).
Almost surely, 254054233212243 is an apocalyptic number.
54054233212243 is a deficient number, since it is larger than the sum of its proper divisors (5164159793837).
54054233212243 is a wasteful number, since it uses less digits than its factorization.
54054233212243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9279.
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 54054233212243 its reverse (34221233245045), we get a palindrome (88275466457288).
The spelling of 54054233212243 in words is "fifty-four trillion, fifty-four billion, two hundred thirty-three million, two hundred twelve thousand, two hundred forty-three".
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