Base | Representation |
---|---|
bin | 110010010111011110… |
… | …000110000100010111 |
3 | 12011120222200011010101 |
4 | 302113132012010113 |
5 | 1341224144400333 |
6 | 40502220234531 |
7 | 3623113460053 |
oct | 622736060427 |
9 | 164528604111 |
10 | 54080856343 |
11 | 20a322628a8 |
12 | a59369ba47 |
13 | 513b361517 |
14 | 28906d0c63 |
15 | 1617c8c67d |
hex | c97786117 |
54080856343 has 16 divisors (see below), whose sum is σ = 56079941632. Its totient is φ = 52098228000.
The previous prime is 54080856341. The next prime is 54080856353. The reversal of 54080856343 is 34365808045.
54080856343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 54080856343 - 21 = 54080856341 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 54080856293 and 54080856302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54080856341) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6598378 + ... + 6606568.
It is an arithmetic number, because the mean of its divisors is an integer number (3504996352).
Almost surely, 254080856343 is an apocalyptic number.
54080856343 is a deficient number, since it is larger than the sum of its proper divisors (1999085289).
54080856343 is a wasteful number, since it uses less digits than its factorization.
54080856343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9166.
The product of its (nonzero) digits is 1382400, while the sum is 46.
The spelling of 54080856343 in words is "fifty-four billion, eighty million, eight hundred fifty-six thousand, three hundred forty-three".
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