Base | Representation |
---|---|
bin | 11000100110100001111010… |
… | …10101101010111010110101 |
3 | 21002112221200111001220022210 |
4 | 30103100331111222322311 |
5 | 24042340143402321123 |
6 | 311021221524044033 |
7 | 14252425160216532 |
oct | 1423207525527265 |
9 | 232487614056283 |
10 | 54100437151413 |
11 | 16268959416114 |
12 | 609903ab33619 |
13 | 2425859779803 |
14 | d50691a7dd89 |
15 | 63c423405e93 |
hex | 31343d56aeb5 |
54100437151413 has 16 divisors (see below), whose sum is σ = 73496438790336. Its totient is φ = 35385724682880.
The previous prime is 54100437151351. The next prime is 54100437151433. The reversal of 54100437151413 is 31415173400145.
It is not a de Polignac number, because 54100437151413 - 29 = 54100437150901 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54100437151433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4358281 + ... + 11278097.
It is an arithmetic number, because the mean of its divisors is an integer number (4593527424396).
Almost surely, 254100437151413 is an apocalyptic number.
54100437151413 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
It is an amenable number.
54100437151413 is a deficient number, since it is larger than the sum of its proper divisors (19396001638923).
54100437151413 is a wasteful number, since it uses less digits than its factorization.
54100437151413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6969044.
The product of its (nonzero) digits is 100800, while the sum is 39.
The spelling of 54100437151413 in words is "fifty-four trillion, one hundred billion, four hundred thirty-seven million, one hundred fifty-one thousand, four hundred thirteen".
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