Base | Representation |
---|---|
bin | 11000100110100001111010… |
… | …10101111101001101011011 |
3 | 21002112221200111012201002112 |
4 | 30103100331111331031123 |
5 | 24042340143412220311 |
6 | 311021221525422535 |
7 | 14252425160651126 |
oct | 1423207525751533 |
9 | 232487614181075 |
10 | 54100437226331 |
11 | 16268959467431 |
12 | 609903ab6aa4b |
13 | 24258597a4942 |
14 | d50691a9d3bd |
15 | 63c42341d28b |
hex | 31343d57d35b |
54100437226331 has 4 divisors (see below), whose sum is σ = 54101761084392. Its totient is φ = 54099113368272.
The previous prime is 54100437226327. The next prime is 54100437226337. The reversal of 54100437226331 is 13362273400145.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54100437226331 - 22 = 54100437226327 is a prime.
It is a super-2 number, since 2×541004372263312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54100437226337) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 661867730 + ... + 661949463.
It is an arithmetic number, because the mean of its divisors is an integer number (13525440271098).
Almost surely, 254100437226331 is an apocalyptic number.
54100437226331 is a deficient number, since it is larger than the sum of its proper divisors (1323858061).
54100437226331 is a wasteful number, since it uses less digits than its factorization.
54100437226331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1323858060.
The product of its (nonzero) digits is 362880, while the sum is 41.
The spelling of 54100437226331 in words is "fifty-four trillion, one hundred billion, four hundred thirty-seven million, two hundred twenty-six thousand, three hundred thirty-one".
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