Search a number
-
+
5410044338137 is a prime number
BaseRepresentation
bin100111010111001111111…
…0001010101111111011001
3201011012021021212202000121
41032232133301111333121
51202114232322310022
615301201241433241
71065601641061615
oct116563761257731
921135237782017
105410044338137
1117a6428a9785a
12734604a9b821
1330321b64504a
14149bc1930345
1595adad352c7
hex4eb9fc55fd9

5410044338137 has 2 divisors, whose sum is σ = 5410044338138. Its totient is φ = 5410044338136.

The previous prime is 5410044338099. The next prime is 5410044338141. The reversal of 5410044338137 is 7318334400145.

5410044338137 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2866963490521 + 2543080847616 = 1693211^2 + 1594704^2 .

It is a cyclic number.

It is not a de Polignac number, because 5410044338137 - 211 = 5410044336089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5410044338093 and 5410044338102.

It is not a weakly prime, because it can be changed into another prime (5410044333137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2705022169068 + 2705022169069.

It is an arithmetic number, because the mean of its divisors is an integer number (2705022169069).

Almost surely, 25410044338137 is an apocalyptic number.

It is an amenable number.

5410044338137 is a deficient number, since it is larger than the sum of its proper divisors (1).

5410044338137 is an equidigital number, since it uses as much as digits as its factorization.

5410044338137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 483840, while the sum is 43.

The spelling of 5410044338137 in words is "five trillion, four hundred ten billion, forty-four million, three hundred thirty-eight thousand, one hundred thirty-seven".