Base | Representation |
---|---|
bin | 11000100110101101000011… |
… | …00000110011000110111001 |
3 | 21002120112002221020010202021 |
4 | 30103112201200303012321 |
5 | 24042434413131214213 |
6 | 311024050510034441 |
7 | 14253026230065451 |
oct | 1423264140630671 |
9 | 232515087203667 |
10 | 54106412757433 |
11 | 162704454a5393 |
12 | 609a2281a8a21 |
13 | 242629c78416a |
14 | d50a9b53cd61 |
15 | 63c672d20d8d |
hex | 3135a18331b9 |
54106412757433 has 8 divisors (see below), whose sum is σ = 54792797230080. Its totient is φ = 53420065614240.
The previous prime is 54106412757431. The next prime is 54106412757461. The reversal of 54106412757433 is 33475721460145.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 54106412757433 - 21 = 54106412757431 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54106412757431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6409348 + ... + 12218533.
It is an arithmetic number, because the mean of its divisors is an integer number (6849099653760).
Almost surely, 254106412757433 is an apocalyptic number.
It is an amenable number.
54106412757433 is a deficient number, since it is larger than the sum of its proper divisors (686384472647).
54106412757433 is a wasteful number, since it uses less digits than its factorization.
54106412757433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18664727.
The product of its (nonzero) digits is 8467200, while the sum is 52.
The spelling of 54106412757433 in words is "fifty-four trillion, one hundred six billion, four hundred twelve million, seven hundred fifty-seven thousand, four hundred thirty-three".
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