Base | Representation |
---|---|
bin | 100111010111110101101… |
… | …0011001111011001001101 |
3 | 201011022112121022000011220 |
4 | 1032233223103033121031 |
5 | 1202124331221441323 |
6 | 15301531105433553 |
7 | 1065645225645462 |
oct | 116575323173115 |
9 | 21138477260156 |
10 | 5411311515213 |
11 | 17a6a1930673a |
12 | 7348b933b8b9 |
13 | 30339102a176 |
14 | 149ca1d49669 |
15 | 95b621e00e3 |
hex | 4ebeb4cf64d |
5411311515213 has 16 divisors (see below), whose sum is σ = 7270168628736. Its totient is φ = 3580099909040.
The previous prime is 5411311515191. The next prime is 5411311515217. The reversal of 5411311515213 is 3125151131145.
5411311515213 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 5411311515213 - 28 = 5411311514957 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5411311515217) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12563331 + ... + 12986912.
It is an arithmetic number, because the mean of its divisors is an integer number (454385539296).
Almost surely, 25411311515213 is an apocalyptic number.
It is an amenable number.
5411311515213 is a deficient number, since it is larger than the sum of its proper divisors (1858857113523).
5411311515213 is a wasteful number, since it uses less digits than its factorization.
5411311515213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25550784.
The product of its digits is 9000, while the sum is 33.
Adding to 5411311515213 its reverse (3125151131145), we get a palindrome (8536462646358).
The spelling of 5411311515213 in words is "five trillion, four hundred eleven billion, three hundred eleven million, five hundred fifteen thousand, two hundred thirteen".
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