Base | Representation |
---|---|
bin | 11000100110111001101110… |
… | …10101010111101100010011 |
3 | 21002121011200102201111202012 |
4 | 30103130313111113230103 |
5 | 24043042334123430001 |
6 | 311031134245013135 |
7 | 14253360032614544 |
oct | 1423346725275423 |
9 | 232534612644665 |
10 | 54113221311251 |
11 | 16273319779673 |
12 | 609b6083b41ab |
13 | 2426b1620932b |
14 | d511458a24cb |
15 | 63c9209202bb |
hex | 313737557b13 |
54113221311251 has 2 divisors, whose sum is σ = 54113221311252. Its totient is φ = 54113221311250.
The previous prime is 54113221311209. The next prime is 54113221311313. The reversal of 54113221311251 is 15211312231145.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54113221311251 - 242 = 49715174800147 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (54113221313251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27056610655625 + 27056610655626.
It is an arithmetic number, because the mean of its divisors is an integer number (27056610655626).
Almost surely, 254113221311251 is an apocalyptic number.
54113221311251 is a deficient number, since it is larger than the sum of its proper divisors (1).
54113221311251 is an equidigital number, since it uses as much as digits as its factorization.
54113221311251 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7200, while the sum is 32.
Adding to 54113221311251 its reverse (15211312231145), we get a palindrome (69324533542396).
The spelling of 54113221311251 in words is "fifty-four trillion, one hundred thirteen billion, two hundred twenty-one million, three hundred eleven thousand, two hundred fifty-one".
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