Base | Representation |
---|---|
bin | 100111010111111001001… |
… | …1100100110101010011011 |
3 | 201011022211221220022100211 |
4 | 1032233302130212222123 |
5 | 1202130102420112311 |
6 | 15301551031311551 |
7 | 1065651213022102 |
oct | 116576234465233 |
9 | 21138757808324 |
10 | 5411431410331 |
11 | 17a6a7aa56711 |
12 | 73493151b5b7 |
13 | 3033acb1841b |
14 | 149cb3c39039 |
15 | 95b6c9c4821 |
hex | 4ebf2726a9b |
5411431410331 has 2 divisors, whose sum is σ = 5411431410332. Its totient is φ = 5411431410330.
The previous prime is 5411431410289. The next prime is 5411431410349. The reversal of 5411431410331 is 1330141341145.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5411431410331 - 215 = 5411431377563 is a prime.
It is a super-2 number, since 2×54114314103312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5411431410293 and 5411431410302.
It is not a weakly prime, because it can be changed into another prime (5411431414331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2705715705165 + 2705715705166.
It is an arithmetic number, because the mean of its divisors is an integer number (2705715705166).
Almost surely, 25411431410331 is an apocalyptic number.
5411431410331 is a deficient number, since it is larger than the sum of its proper divisors (1).
5411431410331 is an equidigital number, since it uses as much as digits as its factorization.
5411431410331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 5411431410331 its reverse (1330141341145), we get a palindrome (6741572751476).
The spelling of 5411431410331 in words is "five trillion, four hundred eleven billion, four hundred thirty-one million, four hundred ten thousand, three hundred thirty-one".
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